Question

For what value of `x` is `sinx=cos19°`, where `0° < x < 90°`?

Answer 1

`x = 71^circ`

Explanation:

By the cofunction identity: `cos(x) = sin(90^circ-x)`, so:

`cos(19^circ)=sin(90^circ-19^circ)=sin(71^circ)`,

so `x = 71^circ`