How do you write the function in standard form #y=1/2(8x-1)^2-3/2#?

1 Answer
Jan 9, 2018

#y=32x^2-8x-1#

Explanation:

#"the equation of a parabola in "color(blue)"standard form"# is.

#•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0#

#"expand the factor "(8x-1)^2" using FOIL"#

#y=1/2(64x^2-16x+1)-3/2#

#"distribute the bracket"#

#y=32x^2-8x+1/2-3/2#

#color(white)(y)=32x^2-8x-1larrcolor(red)"in standard form"#