Question #8e511

1 Answer
Jim S
Jan 9, 2018

Check below.

Explanation:

#f(x)=x+log(cosx)#

Set #g(x)=logx# , #D_g=(0+oo)#

For #f# to be defined in #RR# we need:

#(cosx)##in##D_g#

so #cosx>0#

#cosx=0# #<=># #x=kπ+-π/2# , #k##in##ZZ#

So one could say that #D_f={AA##x##in##RR#: #-π/2##<##x-2kπ##<π/2}# , #k##in##ZZ#

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