If #f( x ) = x ^ { 2} + 2x - 2# what is #f(c+1)#?

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Answer 1 · 2018-01-10T05:19:26

#f(c+1)=c^2+4c+1#

#f(x)=x^2+2x-2#

Replace all the #x#'s with #c+1#

so

#f(c+1)=(c+1)^2+2(c+1)-2#

#f(c+1)=c^2+2c+1+2c+2-2#

#f(c+1)=c^2+2c+1+2c+cancel2-cancel2#

#f(c+1)=c^2+4c+1#