How do you solve #-3+ 6x + 5x = - 3#?

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Answer 1 · 2018-01-10T11:29:10

See a solution process below:

First, combine like terms on the left side of the equation:

#-3 + (6 + 5)x = -3#

#-3 + 11x = -3#

Next, add #color(red)(3)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#color(red)(3) - 3 + 11x = color(red)(3) - 3#

#0 + 11x = 0#

#11x = 0#

Now, divide each side of the equation by #color(red)(11)# to solve for #x# while keeping the equation balanced:

#(11x)/color(red)(11) = 0/color(red)(11)#

#(color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11)) = 0#

#x = 0#