Evaluate log x³+log5x=5log2-log (2/5)?

1 Answer
Jan 11, 2018

x = 2

Explanation:

Before solving this type of question, you must first remember some logarithmic properties,

logx^y = ylogx
logx*y = logx + logy
log(x/y) = logx - logy

logx^3 + log5x = 5log2 - log(2/5)

By applying appropriate properties,

=> 3logx + log5 + logx = 5log2 - (log2 - log5)
=> 4logx = 4log2

Hence,
x = 2

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