How do you solve #-(5- m ) = - ( 3n + 5)#?

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Answer 1 · 2018-01-11T17:42:12

#m=0#

If that instead of #n# it's #m# we have

#-(5- m ) = - ( 3m + 5)# #<=>#

#-5+m=-3m-5# #<=>#

#m=-3m# #<=>#

#m+3m=0# #<=>#

#4m=0# #<=>#

#m=0#