Question #cc0c5

1 Answer
Jan 11, 2018

#y=(12/5)3^x#

Explanation:

#y=ab^x#

Plug in the coordinates:

#12/5=ab^(0)=>a=12/5# ( #b^0=1 #)

plug in value of #a#

#972/5=12/5b^(4)#

#972/12=b^(4)#

#81=b^(4)#

#b=root(4)(81)=>b=+-3#

Since we don't have negative #y# values #b=3#

#:.#

#y=(12/5)3^x#