Solve for x and express the roots in terms of i: #-3x^2+2x=2?#

1 Answer
Jan 12, 2018

#x=1/3+-sqrt5/3i#

Explanation:

#"rearrange into standard form"#

#rArr3x^2-2x+2=0#

#"with "a=3,b=-2" and "c=2#

#"solve using the "color(blue)"quadratic formula"#

#x=(2+-sqrt(4-24))/6#

#color(white)(x)=(2+-sqrt(-20))/6=(2+-2sqrt5i)/6#

#rArrx=1/3+-sqrt5/3i#