How do you solve #-192\leq - 8( 6p - 4) - 8p?#

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Answer 1 · 2018-01-12T21:57:04

#p<= 4#

Start with
#-192<=-8(6p-4)-8p#

Distribute on the right:

#-192<=-48p+32-8p#

collect to terms:

#-192<=-56p+32#

subtract 32 from both sides:

#-224 <=-56p#

divide both sides by #-56# and remember to flip the sign:

#4>= p#

rewrite in the more traditional way:

#p<= 4#