Question

Question #6f584

Answer 1

`2^(11/2)`

Explanation:

The `n`th term of the series is given by `a_n=2*(sqrt(2))^(n-1)`.

The tenth term is `a_(10) = 2(sqrt(2))^9 = 2*(2^(1/2))^9`

`=2*2^(9/2)=2^(11/2)`

Answer 2

`a_(10)=32sqrt2`

Explanation:

`"the n th term of a geometric sequence is "`

`•color(white)(x)a_n=ar^(n-1)`

`"where a is the first term and r the common ratio"`

`"here "a=2" and "r=sqrt2`

`rArra_(10)=2xx(sqrt2)^9`

`["note that "(sqrt2)^2=2]`

`rArra_(10)=2xx2^4sqrt2=2^5sqrt2=32sqrt2`