Question #6f584

2 Answers
Jan 13, 2018

#2^(11/2)#

Explanation:

The #n#th term of the series is given by #a_n=2*(sqrt(2))^(n-1)#.

The tenth term is #a_(10) = 2(sqrt(2))^9 = 2*(2^(1/2))^9#

#=2*2^(9/2)=2^(11/2)#

Jan 13, 2018

#a_(10)=32sqrt2#

Explanation:

#"the n th term of a geometric sequence is "#

#•color(white)(x)a_n=ar^(n-1)#

#"where a is the first term and r the common ratio"#

#"here "a=2" and "r=sqrt2#

#rArra_(10)=2xx(sqrt2)^9#

#["note that "(sqrt2)^2=2]#

#rArra_(10)=2xx2^4sqrt2=2^5sqrt2=32sqrt2#