How do you multiply #(\frac { 2} { 3} ) ( 3c ) ( - 10d ^ { 4} )#?

2 Answers
Nam D.
Jan 14, 2018

#-20cd^4#

Explanation:

#(2/3)*(3c)*(-10d^4)#

#=2/3*3c*-10d^4#

#=2/cancel3*cancel3c*-10d^4#

#=2c*-10d^4#

#=-20cd^4#

Kushagra
Jan 14, 2018

You should know that
#axx(bxxc)=(axxb)xxc=(axxc)xxb#
So.... we can multiply in any order.... but you're also seeing that the first term#(2/3)# has a denominator of #3# and the next term #(3c)# is #3xxc#
So,....
#a/cancelbxxcancelbc=ac#
So... we'll first multiply the first and the second term
#(2/cancel3xxcancel3c)xx(-10d^4)#
That gives us
#(2xxc)xx(-10d^4)#
#2c xx (-10d^4)#
Which simply multiplies to
#-20cd^4#

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