How do you multiply #7( 2m ^ { 2} + 6m - 5)#?

2 Answers
Nam D.
Jan 14, 2018

#14m^2+42m-35#

Explanation:

Expand all terms by #7#.

#7(2m^2+6m-5)#

#=(7*2m^2)+(7*6m)+(7*-5)#

#=(14m^2)+(42m)+(-35)#

#=14m^2+42m-35#

Kushagra
Jan 14, 2018

Well...
#a(b+-c+-d+-e.........)=ab+-ac+-ad+-ae......#
So....
#7(2m^2+6m-5)=(7xx2m^2)+(7xx6m)-(7xx5)#
If you don't know how to multiply these terms.....
#(x=7)(a=2m^2)#
#x xx a=ax#
So... Simply, you'll be like
#7xx2m^2=7xx2xxm^2=14m^2#
Back to the question
#14m^2+42m-35#

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