How do you simplify #(- 2m ^ { 5} n ) ^ { 7}#?

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Answer 1 · 2018-01-14T12:55:05

See a solution process below:

Use these two rule of exponents to simplify this expression:

#a = a^color(red)(1)# and #(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))#

#(-2m^5n)^7 =>#

#(-2^color(red)(1)m^color(red)(5)n^color(red)(1))^color(blue)(7) =>#

#-2^(color(red)(1)xxcolor(blue)(7))m^(color(red)(5)xxcolor(blue)(7))n^(color(red)(1)xxcolor(blue)(7)) =>#

#-2^7m^35n^7 =>#

#-128m^35n^7#