What is the concentration of a #3.951*g# mass of potassium permanganate that is diluted to a #250.0*mL# volume?

1 Answer
anor277
Jan 15, 2018

By definition, #"Concentration"="Moles of solute"/"Volume of solution"#

Explanation:

Now you accurately weighed a mass of potassium permanganate, and then made this up to an accurate #250*mL# volume in a volumetric flask....

And so we take the given quotient....

#underbrace((3.951*g)/(158.03*g*mol^-1))_"moles of potassium permanganate"/underbrace(250.0*mLxx10^-3*L*mL^-1)_"volume of solution"=??*mol*L^-1#...it is precisely the given concentration....

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