Find the square roots of a^2+1/a^2+4i(a+1/a)-2?

1 Answer
Jan 15, 2018

Complete the square

Explanation:

so it can be written as
a^2 + 1/(a^2) -2*a*1/a + 4i(a+1/a) = (a + 1/a)^2 + 4i(a + 1/a)
which is the same as
(a + 1/a)(a + 1/a + 4i)
now take (a + 1/a) = t
hence roots are
t(t+4i)

hence t and t+4i are the solutions

hope u find it helpful :)