Find the square roots of a^2+1/a^2+4i(a+1/a)-2?

1 Answer
Jan 15, 2018

Complete the square

Explanation:

so it can be written as
#a^2 + 1/(a^2) -2*a*1/a + 4i(a+1/a)# = #(a + 1/a)^2 + 4i(a + 1/a)#
which is the same as
#(a + 1/a)(a + 1/a + 4i)#
now take #(a + 1/a) = t#
hence roots are
#t(t+4i)#

hence #t# and #t+4i# are the solutions

hope u find it helpful :)