How do you solve #(q - 3) \times 5= 45#?

Question

582 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-15T23:40:00

See a solution process below:

First, divide each side of the equation by #color(red)(5)# to eliminate the need for parenthesis while keeping the equation balanced:

#((q - 3) xx 5)/color(red)(5) = 45/color(red)(5)#

#((q - 3) xx color(red)(cancel(color(black)(5))))/cancel(color(red)(5)) = 9#

#q - 3 = 9#

Now, add #color(red)(3)# to each side of the equation to solve for #q# while keeping the equation balanced:

#q - 3 + color(red)(3) = 9 + color(red)(3)#

#q - 0 = 12#

#q = 12#