How do you solve #2x + 10= - 20- 4x#?

2 Answers
Jan 16, 2018

#x=-5#

Explanation:

first, add #4x# to both sides of the equation.
#2x+4x+10=-20#
then simplify.
#6x+10=-20#
minus (-) 10 from both sides.
#6x=-20-10#
simplify.
#6x=-30#
then to get #x# on its own,, divide by 6
#x=-5#

Jan 16, 2018

See a solution process below:

Explanation:

First, subtract #color(red)(10)# and add #color(blue)(4x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x + color(blue)(4x) + 10 - color(red)(10) = -20 - color(red)(10) - 4x + color(blue)(4x)#

#(2 + color(blue)(4))x + 0= -30 + 0#

#6x= -30#

Now, divide each side of the equation by #color(red)(6)# to solve for #x# while keeping the equation balanced:

#(6x)/color(red)(6) = -30/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = -5#

#x = -5#