Two charges of $- 1 C$ $-1 C$ and $9 C$ $9 C$ are positioned on a line at points $7$ $7$ and $- 4$ $-4$ , respectively. What is the net force on a charge of $- 3 C$ $-3 C$ at $2$ $2$ ?

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Two charges of $- 1 C$ $-1 C$ and $9 C$ $9 C$ are positioned on a line at points $7$ $7$ and $- 4$ $-4$ , respectively. What is the net force on a charge of $- 3 C$ $-3 C$ at $2$ $2$ ?

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Answer 1 · 2018-01-17T06:37:12

The net force is $= - 5.67 \cdot 10^{9} N$ $=-5.67*10^9N$

Explanation:

The net force between the charges is

$F = k \frac{Q_{1} Q_{3}}{r_{1}^{2}} + k \frac{Q_{2} Q_{3}}{r_{2}^{2}}$ $F=k(Q_1Q_3)/r_1^2+k(Q_2Q_3)/r_2^2$

Where $r$ $r$ is the distance between the charges

The Coulomb Constant is $k = 9 \cdot 10^{9} N \frac{m^{2}}{C^{2}}$ $k=9*10^9Nm^2/C^2$

The charge $Q_{1} = - 1 C$ $Q_1=-1C$ at $(7, 0)$ $(7,0)$

The charge $Q_{2} = 9 C$ $Q_2=9C$ at $(- 4, 0)$ $(-4,0)$

The charge $Q_{3} = - 3 C$ $Q_3=-3C$ at $(2, 0)$ $(2,0)$

The net force is

$F = 910^{9} \cdot \frac{- 1 \cdot - 3}{{(5)}^{2}} + 910^{9} \frac{9 \cdot - 3}{{(6)}^{2}} = - 5.67 \cdot 10^{9} N$ $F=910^9*(-1*-3)/(5)^2+910^9(9*-3)/(6)^2=-5.67*10^9N$

The negative sign indicates that the force is attractive

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Two charges of $- 1 C$ $-1 C$ and $9 C$ $9 C$ are positioned on a line at points $7$ $7$ and $- 4$ $-4$ , respectively. What is the net force on a charge of $- 3 C$ $-3 C$ at $2$ $2$ ?

1 Answer

Explanation:

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Two charges of −1C -1 C and 9C 9 C are positioned on a line at points 7 7 and −4 -4 , respectively. What is the net force on a charge of −3C -3 C at 2 2 ?

1 Answer

Explanation:

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Two charges of $- 1 C$ $-1 C$ and $9 C$ $9 C$ are positioned on a line at points $7$ $7$ and $- 4$ $-4$ , respectively. What is the net force on a charge of $- 3 C$ $-3 C$ at $2$ $2$ ?