Question #4f48c

1 Answer
Jan 17, 2018

A) Boiling point; B) add #"AgNO"_3#; C) add #"Ca(OH)"_2#.

Explanation:

A) Rubbing alcohol and water

The quickest way to differentiate between rubbing alcohol and water is to smell it. Rubbing alcohol has a characteristic strong odour similar to that of ethanol.
I would call this a physical property, but others call it a chemical property because of chemical changes that may occur in the smell receptors in the nose.

However, the boiling point is definitely a physical property.

The boiling point of isopropyl alcohol is 83 °C; the boiling point of water is 100 °C.

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B) Saltwater and water

Add a few drops of a silver nitrate solution to each liquid.

The saltwater will form a white precipitate; the water will not form a precipitate.

http://catalog.flatworldknowledge.com/bookhub/4309?e=averill_1.0-ch03_s05

The formation of a precipitate is a chemical property.

#"AgNO"_3"(aq)" + "NaCl(aq)" → "AgCl(s)" + "NaNO"_3"(aq)"#

C) Carbonated water

Add 1 mL of the liquid to lime water (a saturated solution of calcium hydroxide).

The carbonated water will give a cloudy white precipitate. The water will give no reaction.

http://www.calpoly.edu/~bio/bio161/html/week4.html

The formation of a precipitate is a chemical property.

#"Ca(OH)"_2"(aq)" + "CO"_2"(aq)" → "CaCO"_3"(s)" + "H"_2"O(l)"#