How do I evaluate this limit using Limit Laws?
lim_(x->8)(x+28)^(1/2)/(x+19)^(2/3)
1 Answer
Jan 18, 2018
Please see below.
Explanation:
Ultimately, the limit laws tell us that we can find this limit by substituting
= ((lim_(xrarr8)(x+28))^(1/2))/(lim_(xrarr8)(x+19))^(2/3) if the bottom is not0 .
= (lim_(xrarr8)(x)+lim_(xrarr8)(28))^(1/2)/(lim_(xrarr8)(x)+lim_(xrarr8)(19))^(2/3) if the bottom is not0 .
= ((8)+28)^(1/2)/((8)+19)^(2/3) if/because the bottom is not0
= 36^(1/2)/27^(2/3)
= 6/9 = 2/3