Two charges of $6 C$ and $-3 C$ are positioned on a line at points $-7$ and $5$ , respectively. What is the net force on a charge of $-3 C$ at $2$ ?

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Answer 1 · 2018-01-20T06:37:12

The net force is $=9*10^9N$

The net force between the charges is

$F=k(Q_1Q_3)/r_1^2+k(Q_2Q_3)/r_2^2$

Where $r$ is the distance between the charges

The Coulomb Constant is $k=9*10^9Nm^2/C^2$

The charge $Q_1=6C$ at $(-7,0)$

The charge $Q_2=-3C$ at $(5,0)$

The charge $Q_3=-3C$ at $(2,0)$

The net force is

$F=910^9*(6*-3)/(9)^2+910^9(-3*-3)/(3)^2=9*10^9N$

The positive sign indicates that the force is repulsive

Two charges of 6 C 6 C and -3 C -3 C are positioned on a line at points -7 -7 and 5 5 , respectively. What is the net force on a charge of -3 C -3 C at 2 2 ?