How do you simplify #y^ { - 1} \cdot y ^ { 20} \cdot y ^ { 39}#?

1 Answer
Jan 20, 2018

See a solution process below:

Explanation:

Use this rule of exponents to simplify the expression:

#x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))#

#y^color(red)(-1) * y^color(blue)(20) * y^color(green)(39) => y^(color(red)(-1)+color(blue)(20)+y^color(green)(39)) => y^(color(red)(-1)+59) => y^58#