How do you simplify #(\frac { r ^ { 5} } { r ^ { 16} } ) ^ { - 2}#?

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Answer 1 · 2018-01-21T00:43:34

Please see the step process below...

Having;

#(r^5/r^16)^-2#

Recall indices; #x^a/x^b = x^(a - b)#

Hence;

#(r^5/r^16)^-2 = (r^(5 - 16))^-2#

#rArr (r^-11)^-2#

#rArr r^( - 11 xx - 2)#

#rArr r^22#