Question

Question #d2b73

Answer 1

The oxidation number of Mn in permanganate ion is +7.

Explanation:

The sum of O.N of all atoms of an ion is equal to the charge.
In permanganate ion (`MnO_4^-`), there are four O atoms and one Mn atom.

Let's take O.N of Mn as x. O.N of oxygen is usually taken as -2.

`x+(-2)*4=-1`
`x=+7`