Question

Two charges of `-5 C` and `-7 C` are positioned on a line at points `5` and `4`, respectively. What is the net force on a charge of `-5 C` at `0`?

Answer 1

`28.68×10^9` N along negative `X` axis

Explanation:

Here, the `-5C` charge at `x=5` tries to push the `-5C` charge at `x=0`

And the value of that force is `F1` = `9×10^9×(-5)×(-5)/(5^2) N` or `9×10^9 N`

The `-7C` charge at `x=4` also tries to push it away due to repulsion in the same direction.

And,the value of that force is `F2 = 9×10^9×(-7)×(-5)/(4^2) N` i.e `19.68×10^9 N`

So,total repulsive force towards negative `X` axis is `F1+F2` i.e `(9+19.68)×10^9 N` or `28.68×10^9 N`