Find all values of c such that cc−5=4c−4. Help, Please?

1 Answer
MathFact-orials.blogspot.com
Jan 23, 2018

There are no real values of c that will make this equation work. However, there are imaginary solutions: c=−4+2i,−4−2i

Explanation:

cc−5=4c−4

Cross multiply:

c(c−4)=4(c−5)

Distribute:

c2−4c=4c−20

Set equal to 0:

c2−8c+20=0

I'll use the quadratic formula:

x=−b±√b2−4ac2a

with a=1,b=−8,c=20

x=−8±√(−8)2−4(1)(20)2(1)

x=−8±√64−802

There are no real solutions to this problem. There are, however, imaginary solutions:

x=−8±√−162=−8±4i2

x=−4+2i,−4−2i

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