How do you solve #9u ^ { 2} - 24u + 16=0#?
1 Answer
Jan 23, 2018
Explanation:
Note that:
#(A-B)^2 = A^2-2AB+B^2#
In our example, both
#0 = 9u^2-24u+16#
#color(white)(0) = (3u)^2-2(3u)(4)+4^2#
#color(white)(0) = (3u-4)^2#
Hence:
#u = 4/3" "# with multiplicity#2#