Question

How could `"zinc chloride"` be prepared?

Answer 1

FIRST, you need anything that contains either zinc and/or chloride. Then you need to make sure that they will combined to give you a product of `ZnCl_2`.

The easiest one would be to just dissolve zinc metal in hydrochloric acid:
`Zn + 2HCl -> ZnCl_2 + H_2 (g)`

Answer 2

Zinc metal and chlorine gas....

Explanation:

And we can represent this by the redox reaction....

`Zn(s) + Cl_2(g) stackrel(Delta)rarrZnCl_2(s)`

The metal is oxidized, and chlorine gas is reduced.....

Of course you could oxidize the metal by the action of hydrochloric acid...

`Zn(s) + 2HCl(aq) rarr ZnCl_2(aq) +H_2(g)uarr`

Answer 3

See below:

Explanation:

A safe and easy method is to choose a suitable base such as zinc oxide or zinc carbonate.

XS base is added to dilute hydrochloric acid. The mixture is filtered and the zinc chloride solution is crystallised.

`sf(ZnO_((s))+2HCl_((aq))rarrZnCl_(2(aq))+H_2O_((l))`

or

`sf(ZnCO_(3(s))+2HCl_((aq))rarrZnCl_(2(aq))+CO_(2(g))+H_2O_((l)))`