How do you solve this system of equations: #5y + 4x = 3 and 5x + 2y = 8#?

1 Answer
Jim G.
Jan 24, 2018

#(x,y)to(2,-1)#

Explanation:

#4x+5y=3to(1)#

#5x+2y=8to(2)#

#"multiply equation "(1)" by 2 and equation "(2)" by 5"#

#rArr8x+10y=6to(3)#

#rArr25x+10y=40to(4)#

#"subtracting these equations will eliminate y from them"#

#"subtract "(4)-(3)" term by term"#

#(25x-8x)+(cancel(10y-10y)^0)=(40-6)#

#rArr17x=34#

#"divide both sides by 17"#

#rArrx=2#

#"substitute this value into "(1)" or "(2)#

#(1)to8+5y=3#

#rArr5y=3-8=-5#

#"divide both sides by 5"#

#rArry=-1#

#rArr"the point of intersection "=(2,-1)#

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