Question

A container was found in the home of the victim that contained 103 g of ethylene glycol in 340 g of liquid. What was the percentage of ethylene glycol?

Answer 1

So are we talking murder or suicide....or was the man a dipso...?

Explanation:

Ethylene glycol poisoning is not so readily apparent, in that the victim may display symptoms that are consistent with those of intoxication (i.e. over consumption of `H_3C-CH_2OH`).

To get the percentage of ethylene glycol we take the quotient...

`"mass of ethylene glycol"/"mass of solution"xx100%=`

`(103*g)/(340*g)xx100%=30.3%(m"/"m)`...