Question

How do you multiply `4n ^ { 0} \cdot 4m ^ { - 3} n ^ { - 1}`?

Answer 1

`4m^-3n^-1`

Explanation:

Well, know that `n^0=1` for all `ninRR, n!=0`.

`:.4n^0=4`

`:.4n^0*4m^-3*n^-1=4*4m^-3n^-1`

The only like-terms left are the whole numbers, so we multiply them. `(4*4=16)`

`=16m^-3n^-1`

Answer 2

`16/(m^3n)`

Explanation:

Everything in this is multiplied since there's no addition or subtraction or division symbol.
So
1, 4 times 4 is 16
2. Anything to the power of 0 is 1, so you just kind of discard that thing since anything times 1 doesn't change.
3. Anything to the negative power just means that it is one over the thing, so `m^-3` becomes `1/m^3`

Put everything together, and you'll get the answer