The voltage of a certain thermocouple as a function of the temperature is given by E = 2.800T + 0.006#(T∧2)#. If the temperature is increasing at the rate of 1.00°C/min,how fast is the voltage increasing when T=100°C?
1 Answer
Jan 25, 2018
The voltage is increasing at the rate of
Explanation:
The relation is
Differentiating with respect to
Here,
and
Therefore,