Question

Question #5dd43

Answer 1

Here's four values of `x` and what you get when you plug them into `B(x)`:

`color(white)"....." x color(white)"---------" B(x)"`
`"------------------------"`
`color(white)".." -2 color(white)"----------" 19`
`color(white)"....." 0 color(white)"------....." 18`
`color(white)".--"55 color(white)"-----..." -9.5`
`color(white)"--"5.5 color(white)"--------.." 15.25`

Explanation:

I am not quite sure what is being asked, but I will try my best to respond in a way that answers any questions you may have.

The function you gave is:

`B(x) = 18 - 0.5x`

I believe you need to find the value of the function for different values of `x`.

You listed `-2, 0,`and `55`, which I believe may be a typo of `5.5`

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You can find the value of `B(x)` for a certain `x` value by substituting the other number for `x` in the equation.

After all, the function `B(x)` is just a set of instructions for what to do with `x` to get the value you want.

So, let's plug in some numbers and see what we get:

`B(color(red)(-2)) = 18 - 0.5(color(red)(-2)) = 18 + 1 =19`

`B(color(blue)0) = 18 - 0.5(color(blue)0) = 18 + 0 = 18`

`B(color(orange)55) = 18 - 0.5(color(orange)55) = 18 - 27.5 = -9.5`

`B(color(limegreen)5.5) = 18 - 0.5(color(limegreen)5.5) = 18 - 2.75 = 15.25`

So there's four values of `B(x)` and how we got them!

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Again, you may not need all of this information, or this may be exactly what you were looking for. However, if this isn't what you were asking for, please respond so I can answer any other questions you may have. I would be happy to help you with anything else you need!

Hope this helps!