Question

Question #97e4c

Answer 1

`"MgO"` is the empirical formula.

Explanation:

`"mol of Mg" = "4.9 g" /"24 g/mol" = "0.2 mol"`

`"mol of O" = "3.2 g"/"16 g/mol" = "0.2 mol"`

So the mole ratio is

`0.2: 0.2 = 1:1`

Therefore, `"Mg"_1"O"_1 = "MgO"` is the empirical formula.