How do you solve $6 (1 - x) = 4 (1 + 2 x) + 6$ $6( 1- x ) = 4( 1+ 2x ) + 6$ ?

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Answer 1 · 2018-01-27T04:33:11

$x = - \frac{2}{7}$ $x=-2/7$

$6 (1 - x) = 4 (1 + 2 x) + 6$ $6(1-x)=4(1+2x)+6$

Expand all brackets.

$6 - 6 x = 4 + 8 x + 6$ $6-6x=4+8x+6$

Combine like-terms.

$6 - 6 x = 10 + 8 x$ $6-6x=10+8x$

Isolate $x$ $x$ onto one side.

$6 = 10 + 14 x$ $6=10+14x$

Subtract $10$ $10$ from both sides to eliminate the $10$ $10$ on the $R H S$ $RHS$ .

$- 4 = 14 x$ $-4=14x$

Divide by $14$ $14$ to get $x$ $x$ .

$x = - \frac{4}{14}$ $x=-4/14$

Simplify the fraction by dividing by $2$ $2$ .

$x = - \frac{2}{7}$ $x=-2/7$

How do you solve 6(1−x)=4(1+2x)+66( 1- x ) = 4( 1+ 2x ) + 6?