How do you solve #6( 1- x ) = 4( 1+ 2x ) + 6#?

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Answer 1 · 2018-01-27T04:33:11

#x=-2/7#

#6(1-x)=4(1+2x)+6#

Expand all brackets.

#6-6x=4+8x+6#

Combine like-terms.

#6-6x=10+8x#

Isolate #x# onto one side.

#6=10+14x#

Subtract #10# from both sides to eliminate the #10# on the #RHS#.

#-4=14x#

Divide by #14# to get #x#.

#x=-4/14#

Simplify the fraction by dividing by #2#.

#x=-2/7#