Question

Question #b0450

Answer 1

`2C_4H_10+13O_2=8CO_2+10H_2O`

As per the above balanced equation of the given equation the interacting ratio of number of moles of reactants is

`("moles of "O_2)/("moles of "C_4H_10)=13/2`

Molar mass of `C_4H_10=(4*12+10*1)=58gmol^-1`

Molar volume of a gas at STP `22.4L`

So we can write

`("At STP Volume of "O_2)/("mass of "C_4H_10)=(13xx22.4)/(2xx58)Lg^-1`

`=(13xx22.4xx1000)/(2xx58)Lkg^-1`

`~~2510.34Lkg^-1`

So at STP the volume of oxygen needed for complete combustion of 1kg of butane will be

`~~2510.34L`