Question

If a projectile is shot at a velocity of `28 m/s` and an angle of `pi/12`, how far will the projectile travel before landing?

Answer 1

`39.2 m`

Explanation:

Range of projectile is given as `u^2 sin (2theta)/g` (derivation done using the equation `R=u cos theta*T` and `T=2u sin theta/g` , where, `R` stands for range, `T` for total time of flight, `theta` is angle of projection and `u` is the velocity of projection)

Given, `u= 28 m/s` and `theta= pi/12`

So, `R = 39.2m`