Question

What is the moment of inertia of a pendulum with a mass of `8 kg` that is `16 m` from the pivot?

Answer 1

As,here the radius of the bob of the pendulum is not mentioned,so we shall have to consider the bob to be a point mass.

Therefore,moment of inertia of a point mass `m` located at a distance of `r` from a point is `m×r^2`

Given,`m=8 Kg` & `r=16m`

So,the value becomes `2048 Kg.m^2`