How do you write the function in standard form #y=8(x+7)^2-20#?

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Answer 1 · 2018-01-28T00:40:03

#8x^2+112x+372#

We want our final form to be #ax^2+bx+c#

Let's expand this:

#8(x+7)(x+7)-20#

#8(x^2+14x+49)-20#

distribute the #8#

#8x^2+112x+392-20#

#8x^2+112x+372#