How many moles are present in the following 50 g of calcium carbonate and 1.6 grams of sodium hydroxide?

1 Answer
Surya K.
Jan 28, 2018

#0.5mol# calcium carbonate, #0.04mol# sodium hydroxide

Explanation:

Well, the formula for moles is #n=m/M#, where #m# is the given mass and #M# the molar mass.

For calcium carbonate, #m=50g#, #M=100g#. So #50/100=0.5mol#

For sodium hydroxide, #m=1.6g#, #M=40g#. So #1.6/40=0.04mol#.

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