Question

Question #dd9aa

Answer 1

This requires 8.38 kJ of energy.

Explanation:

The heat of vapourization of ethanol is 38.6 kJ/mol. (This is a quantity you look up when you need it.)

Since the molar mass of ethanol (`C_2H_6O`) is 46 g, the 10.0 g sample is

`(10.0 g)/(46.0g/"mol") = 0.217` mol

Therefore, the energy needed is

`0.217 "mol" xx 38.6 (kJ)/"mol" = 8.38 kJ`