How do you evaluate (- 7k + 2s - 3q ) - ( - 2q - 3k ) + ( 4k + q - 2s )?

1 Answer
Jan 30, 2018

0

Explanation:

Let’s start by making the equation to addition format (as it is easier to evaluate).

Note: Negative x Negative = Positive

So (-7k+2s-3q)-(-2q-3k)+(4k+q-2s)

Becomes (-7k+2s-3q)+(2q+3k)+(4k+q-2s)

Now we can group all the like terms together; move all the same variables together. Ill arrange it in brackets for you to get a better visual.

(-7k+2s-3q)+(2q+3k)+(4k+q-2s)

(-7k+3k+4k)+(2s-2s)+(-3q+2q+q)

(-7k+7k)+(2s-2s)+(-3q+3q)

0 + 0 + 0 = 0

Therefore answer is 0