Question

Question #e60d6

Answer 1

`8.22*10^14` `"Hz"` or `"/s"`.

Explanation:

To find the frequency, we'll need to use this equation:

`c=lambda*nu`, where
`lambda` is the wavelength, `nu` is the frequency, and `c` is the speed of light at `3.0*10^8` `"m/s"`.

We already know both the speed of light, which is a constant, and the frequency, which had been given to us in the question. So, just plug the values in and solve for `nu`!

`c=lambda*nu`
`3.0*10^8 "m/s" = 3.65*10^-7"m"*nu`
`nu = (3.0*10^8 "m/s")/(3.65*10^-7"m") = 8.2191 * 10^14` `"Hz"`

`3` significant figures were given in the question, so our answer would be `8.22*10^14` `"Hz"`

Answer 2

Please see the step process below;

Explanation:

`c = flambda`

Where;

`c = 3 xx 10^8ms^-1` (Is constant for all electromagnetic wave)

`lambda = 3.65 xx 10^-7m` (wave length)

`f = ?` (frequency)

`c = flambda`

Making `f` the subject formula..

`f= c/lambda`

Substituting the parameters..

`f = (3 xx 10^8)/(3.65 xx 10^-7)`

`f = 3/(3.65) xx 10^(8-(-7))`

`f = 0.8219 xx 10^(8+7)`

`f = 0.8219 xx 10^15`

`f = 8.22 xx10^14Hz`