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Why is #CH-=C^-# more stable than #CH_2=CH^-# ?

1 Answer
Al E. · jonathan n.
Jan 30, 2018

The hybridization of the carbons in each molecule determines the stability of the negative charge in this case.

Consider,

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where each carbon in the first molecule is #"sp"# hybridized, and each carbon in the second molecule is #"sp"^2# hybridized.

Hence, the electrons in the an #"sp"# orbital are more stable than electrons in an #"sp"^2# orbital because they are closer to the positively charged nucleus.

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