How do you solve #-( x - 5) = 5x - 1#?

1 Answer
Jan 30, 2018

See a solution process below:

Explanation:

First, remove the parenthesis on the left side of the equation being careful to manage the signs of the individual terms correctly:

#-x + 5 = 5x - 1#

Next, add #color(red)(x)# and #color(blue)(1)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-x + color(red)(x) + 5 + color(blue)(1) = 5x + color(red)(x) - 1 + color(blue)(1)#

#0 + 6 = 5x + 1color(red)(x) - 0#

#6 = (5 + 1)color(red)(x)#

#6 = 6x#

Now, divide each side of the equation by #color(red)(6)# to solve for #x# while keeping the equation balanced:

#6/color(red)(6) = (6x)/color(red)(6)#

#1 = (color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6))#

#1 = x#

#x = 1#