How do you evaluate #(4- 7) ^ { 2} \div ( 7- 6) ^ { 3}#?

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Answer 1 · 2018-01-31T05:21:12

9

#(4-7)^2=9#
#(7-6)^3=1#
#9÷1=9#

Answer 2 · 2018-02-01T17:45:33

#(4-7)^2-:(7-6)^3=color(blue)9#

We will need to use the order of operations represented by the acronym PEMDAS.

P=parentheses and brackets
E=exponents or powers
MD=multiplication and division from left to right.
AS=addition and subtraction from left to right.

#(4-7)^2-:(7-6)^3#

Simplify the parentheses first.

#(-3)^2-:(1)^3#

Now simplify the exponents.

#9-:1#

Simplify.

#9#