Question #89b68

1 Answer
Munu
Jan 31, 2018

#4Na + O_2-> 2Na_2O#

Mass of 1 mole of sodium is 22.99 g. Therefore, 9.5 g is equivalent to #9.5/22.99 # moles., that is, 0.413 mole of sodium.

4 moles of Na require 1 mole of #O_2#.
0.413 mole of Na would therefore require #(1/4)*0.413# moles of #O_2#.

Solving this, we get,

0.1033 moles of oxygen is needed to completely react with 9.5 g of Na.

Related questions
Impact of this question
3303 views around the world
You can reuse this answer
Creative Commons License