How do you simplify #\frac { \frac { x ^ { 2} + x ^ { 2} } { x y } - 2} { \frac { 4x ^ { 2} - 4x ^ { 2} } { 2x y } }#?
2 Answers
This ends up as a division by 0, so it is undefined.
Explanation:
Simplify
1) For clarity, write this as one fraction divided by the other
2) Combine the like terms in the numerators
3) To divide fractions, multiply by the reciprocal of the divisor
4) No matter how you simplify the fractions, this problem is still going to end with a division by
I guess you know what happened the last time someone divided by
https://animalderuta.com/2013/05/02/la-matematica-y-el-cero/
I think the question and answer should have been more like:
#((x^2+y^2)/(xy)-2)/((4x^2-4y^2)/(2xy)) = (x-y)/(2(x+y))#
with exclusions
Explanation:
I suspect a couple of typos in the question, so here's an answer if the question should have been to simplify:
#((x^2+y^2)/(xy)-2)/((4x^2-4y^2)/(2xy))#
Multiplying both numerator and denominator by
#(x^2-2xy+y^2)/(2(x^2-y^2)) = (color(red)(cancel(color(black)((x-y))))(x-y))/(2color(red)(cancel(color(black)((x-y))))(x+y)) = (x-y)/(2(x+y))#
with exclusions