Question

Question #631b1

Answer 1

`(x + 3)(2x + 1)=0`

Explanation:

`2(x + 3)^2 = 5(x + 3)`
`2(x + 3)^2 - 5(x + 3) = 0`
`(x + 3)[2(x + 3) - 5] = 0`
`(x + 3) (2x + 6 - 5) = 0`
`(x + 3)(2x + 1) = 0`
`x=-3, -1/2`